# How do you find the product of (3ab)/(4c^4)*(16c^2)/(9b)?

Nov 13, 2016

$\frac{4 a}{3 {c}^{2}}$

#### Explanation:

Step 1) Multiple both terms in the numerators of the fractions and multiple both terms in the denominators of the fractions:

$\frac{3 a b \cdot 16 {c}^{2}}{4 {c}^{4} 9 b}$

$\frac{48 a b {c}^{2}}{36 b {c}^{4}}$

Step 2) Separate like terms to simplify:

$\left(\frac{48}{36}\right) a \left(\frac{b}{b}\right) \left({c}^{2} / {c}^{4}\right)$

$\left(\frac{12}{12}\right) \left(\frac{4}{3}\right) a \left(1\right) \left(\frac{1}{c} ^ \left(4 - 2\right)\right)$

$\left(\frac{4}{3}\right) a \left(\frac{1}{c} ^ 2\right)$

Step 3) Combine all of the terms back again for the final simplification:

$\frac{4 a}{3 {c}^{2}}$