How do you find the product of #(3ab)/(4c^4)*(16c^2)/(9b)#?

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Answer 1 · 2016-11-13T22:57:26

#(4a)/(3c^2)#

Step 1) Multiple both terms in the numerators of the fractions and multiple both terms in the denominators of the fractions:

#(3ab*16c^2)/(4c^4 9b)#

#(48abc^2)/(36bc^4)#

Step 2) Separate like terms to simplify:

#(48/36)a(b/b)(c^2/c^4)#

#(12/12)(4/3)a(1)(1/c^(4-2))#

#(4/3)a(1/c^2)#

Step 3) Combine all of the terms back again for the final simplification:

#(4a)/(3c^2)#