How do you find the quotient and remainder when $\frac{x^{3} - 6 x^{2} - 9 x + 3}{x - 3}$ $(x^3-6x^2-9x+3)/(x-3)$ ?

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Answer 1 · 2015-11-11T09:54:41

Long division is the best way to find the quotient ( $x^{2} - 3 x - 18$ $x^2 - 3x - 18$ ) and the remainder ( $- 51$ $-51$ )

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How do you find the quotient and remainder when (x^3-6x^2-9x+3)/(x-3)x3−6x2−9x+3x−3(x^3-6x^2-9x+3)/(x-3)?