Question

How do you find the quotient of the complex numbers and express your answer in trigonometric form `(5(cos(15º) + i sin(15º)))/(3(cos(70º) + i sin(70º)))`?

Answer 1

`(5/3)( cos 55^o - i sin 55^o )`.

Explanation:

Use `e^(+-itheta)=cos theta +- i sin theta`.

The ratio = `(5/3)e^(i15^o)/e^(i70^o)`

`=(5/3)e^(i(15-70)^o)`

`=(5/3)( cos 55^o - i sin 55^o)`