How do you find the real and imaginary part 12i^12 + pi(i)?
1 Answer
Mar 22, 2016
Explanation:
Note that we can simplify
{(i=color(red)(sqrt(-1))),(i^2=(color(red)(sqrt(-1)))^2=color(blue)(-1)),(i^4=(i^2)^2=(color(blue)(-1))^2=color(green)1),(i^12=(i^4)^3=color(green)1^3=1):}
Thus, the expression simplifies to be:
12i^12+pii=12(1)+pii=12+pii
This is a complex number in the form
a+bi
where