# How do you find the real and imaginary part #12i^12 + pi(i)#?

##### 1 Answer

Mar 22, 2016

#### Explanation:

Note that we can simplify

#{(i=color(red)(sqrt(-1))),(i^2=(color(red)(sqrt(-1)))^2=color(blue)(-1)),(i^4=(i^2)^2=(color(blue)(-1))^2=color(green)1),(i^12=(i^4)^3=color(green)1^3=1):}#

Thus, the expression simplifies to be:

#12i^12+pii=12(1)+pii=12+pii#

This is a complex number in the form

#a+bi#

where