# How do you find the remainder when #1.f(x)=x^3+2x^2-6x+8; x+4#?

##### 1 Answer

Mar 22, 2018

The remainder is

#### Explanation:

The remainder theorem tell us that if we divide a polynomial

Thus the remainder we seek for:

# f(x) = x^3+2x^2-6x+8 #

divided by

# f(-4) = (-4)^3+ 2(-4)^2-6(-4)+8 #

# \ \ \ \ \ \ \ \ \ \ \ = -64+ 32+24+8 #

# \ \ \ \ \ \ \ \ \ \ \ = 0 #

And we can conclude that