How do you find the remainder when 1.f(x)=x^3+2x^2-6x+8; x+4?
1 Answer
Mar 22, 2018
The remainder is
Explanation:
The remainder theorem tell us that if we divide a polynomial
Thus the remainder we seek for:
f(x) = x^3+2x^2-6x+8
divided by
f(-4) = (-4)^3+ 2(-4)^2-6(-4)+8
\ \ \ \ \ \ \ \ \ \ \ = -64+ 32+24+8
\ \ \ \ \ \ \ \ \ \ \ = 0
And we can conclude that