How do you find the remainder when $x^{3} - 19 x - 30$ $x^3-19x-30$ is divided by x-3?

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Answer 1 · 2016-09-09T08:14:17

See explanation.

To find a remainder from division by a polynomial $x - a$ $x-a$ it is enough to substitute $a$ $a$ for $x$ $x$ in the polynomial.

Here:

$W (x) = x^{3} - 19 x - 30$ $W(x)=x^3-19x-30$

$W (3) = 3^{3} - 19 \cdot 3 - 30 = 27 - 57 - 30 = - 60$ $W(3)=3^3-19*3-30=27-57-30=-60$

How do you find the remainder when x3−19x−30x^3-19x-30 is divided by x-3?