How do you find the remainder when x^3-7x^2+14x-8 is divided by x+1?

Oct 30, 2016

The remainder is $= - 30$

Explanation:

Let $f \left(x\right) = {x}^{3} - 7 {x}^{2} + 14 x - 8$
Then we calculate
$f \left(- 1\right) = {\left(- 1\right)}^{3} - 7 \cdot {\left(- 1\right)}^{2} + 14 \left(- 1\right) - 8 = - 30$
So the remainder is $= - 30$

You can also do a long division