How do you find the remainder when x^5-2x^4-3x^3+4x^2+3x+6 is divided by x-1?

1 Answer
Jun 7, 2017

Remainder is 9

Explanation:

x-1=0 :. x= 1

x^5 -2x^4-3x^3+4x^2+3x+6

By putting x=1 in the equation we can find remainder (R).

R=1^5-2*1^4-3*1^3+4*1^2+3*1+6=1-2-3+4+3+6= 14-5=9 [Ans]