# How do you find the rest of the zeros given one of the zero #c=2/3# and the function #f(x)=3x^3+4x^2-x-2#?

##### 1 Answer

Dec 3, 2016

The zeros of

#### Explanation:

The given zero corresponds to a linear factor

#3x^3+4x^2-x-2 = (3x-2)(x^2+2x+1)#

We can recognise the remaining quadratic factor as the perfect square trinomial:

#x^2+2x+1 = (x+1)^2#

So the other zeros are both