How do you find the rest of the zeros given one of the zero c=2/3 and the function f(x)=3x^3+4x^2-x-2?
1 Answer
Dec 3, 2016
The zeros of
Explanation:
The given zero corresponds to a linear factor
3x^3+4x^2-x-2 = (3x-2)(x^2+2x+1)
We can recognise the remaining quadratic factor as the perfect square trinomial:
x^2+2x+1 = (x+1)^2
So the other zeros are both