How do you find the roots of #2m^2-7m-13=-10# using the quadratic formula?

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Answer 1 · 2017-08-08T09:55:46

#(7+-sqrt73)/-4#

First, we must make the equation into the form of

#ax^2+bx+c#

in order to use the quadratic formula. Adding 10 to both sides of the equation gives us

#2m^2-7m-3#

This equation is in the form mentioned above and thus we can now use the quadratic equation to the roots

#a= 2, b=-7, c=-3#

We substitute these value into the equation to give us

#(-(-7)+-sqrt((-7)^2-4(2)(-3)))/(-2*(2))#

Thus, the roots to the equation #2m^2-7m-13=-10# would be

#(7+-sqrt73)/-4#