How do you find the slope of #6y ^ { 4} + 7x ^ { 4} = 5y + 8x # at #(1,1)#?

1 Answer
bp
Jun 5, 2017

#-20/19#

Explanation:

Differentiate w.r.t x. It would be# 24y^3 dy/dx +28x^3 = 5 dy/dx +8#

Solve for dy/dx,

#(24y^3 -5) dy/dx= 8-28x^3#

Slope is #dy/ dx# for all values of x and y. For x=1 and y=1 it would be # (24-5)dy/dx=(8-28)#

Thus required slope is #dy/dx=-20/19#

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