# How do you find the slope of a line perpendicular to 2x+3y=5?

If you call the slope of your line $m$ the slope of the line perpendicular to it will be: ${m}_{1} = - \frac{1}{m}$
Your line can be written in the form $y = m x + b$ isolating $y$ on one side as:
$y = - \frac{2}{3} x + \frac{5}{3}$
The slope will then be: $m = - \frac{2}{3}$
The slope of the perpendicular will then be: ${m}_{1} = - \frac{1}{m} = \frac{3}{2}$