Question

How do you find the slope of a line perpendicular to the line passing through the given points P(6,-1) and Q(3,-2)?

Answer 1

A line passing through `(6,-1)` and `(3,2)`
has a slope of
`m = ((-1)-(-2))/(6-3)`
`= 1/3`

If a line has slope `m`
then any line perpendicular to it has slope`(-1/m)`

The slope of a line perpendicular to the line passing through the given points P(6,-1) and Q(3,-2) is `(-3)`