# How do you find the slope of a line perpendicular to the line passing through the given points P(6,-1) and Q(3,-2)?

A line passing through $\left(6 , - 1\right)$ and $\left(3 , 2\right)$
$m = \frac{\left(- 1\right) - \left(- 2\right)}{6 - 3}$
$= \frac{1}{3}$
If a line has slope $m$
then any line perpendicular to it has slope$\left(- \frac{1}{m}\right)$
The slope of a line perpendicular to the line passing through the given points P(6,-1) and Q(3,-2) is $\left(- 3\right)$