Question

How do you find the slope of a tangent line to the graph of the function `F(t)= 3- (8/3t)` at point: (2/4, -7/3)?

Answer 1

There is no such line.

Explanation:

The point `(2/4,-7/3)` is not on the graph of that function.

But at any point `(a/b)` that is on the graph, the slope of the tangent line is the same as the slope of the line.

So it is `-8/3`