Question

How do you find the slope of a tangent line to the graph of the function`F(x)=x^2 - 3` at (-4,13)?

Answer 1

Take the derivative of the function `F(x)`

`F'(x) = 2x`

Plug in your `x` value: `-4`

`F'(-4) = 2(-4) = -8`

This is your slope of the tangent line at point `(-4, 13)`