How do you find the slope of a tangent line to the graph of the function f(x)=x^3-2x+1 at (2,5)? Calculus Derivatives Tangent Line to a Curve 1 Answer Sasha P. Sep 21, 2016 k=10 Explanation: (x_0,y_0)=(2,5) y=kx+n k=f'(x_0) f'(x)=3x^2-2 => f'(x_0) = f'(2)=10 k=10 Answer link Related questions How do you find the equation of a tangent line to a curve? How do you find the slope of the tangent line to a curve at a point? How do you find the tangent line to the curve y=x^3-9x at the point where x=1? How do you know if a line is tangent to a curve? How do you show a line is a tangent to a curve? How do you find the Tangent line to a curve by implicit differentiation? What is the slope of a line tangent to the curve 3y^2-2x^2=1? How does tangent slope relate to the slope of a line? What is the slope of a horizontal tangent line? How do you find the slope of a tangent line using secant lines? See all questions in Tangent Line to a Curve Impact of this question 2253 views around the world You can reuse this answer Creative Commons License