Question

How do you find the slope of a tangent line to the graph of the function `f(x)=x^3-2x+1` at (2,5)?

Answer 1

`k=10`

Explanation:

`(x_0,y_0)=(2,5)`

`y=kx+n`
`k=f'(x_0)`

`f'(x)=3x^2-2 => f'(x_0) = f'(2)=10`

`k=10`