How do you find the slope of the tangent line to the curve # y = x − x^5# at the point (1, 0)? Calculus Derivatives Tangent Line to a Curve 1 Answer Michael Jun 29, 2015 Slope = -4 Explanation: #y=x-x^5# #(dy)/(dx)=1-5x^4# Since #x=1#: #(dy)/(dx)=1-(5xx1)=-4# Answer link Related questions How do you find the equation of a tangent line to a curve? How do you find the slope of the tangent line to a curve at a point? How do you find the tangent line to the curve #y=x^3-9x# at the point where #x=1#? How do you know if a line is tangent to a curve? How do you show a line is a tangent to a curve? How do you find the Tangent line to a curve by implicit differentiation? What is the slope of a line tangent to the curve #3y^2-2x^2=1#? How does tangent slope relate to the slope of a line? What is the slope of a horizontal tangent line? How do you find the slope of a tangent line using secant lines? See all questions in Tangent Line to a Curve Impact of this question 1282 views around the world You can reuse this answer Creative Commons License