How do you find the slope of the tangent line to the graph of the given function #y= -x^-3+x^-2#; x=2?
1 Answer
May 4, 2018
Explanation:
#"the slope of the tangent is the value of "dy/dx" at x = 2"#
#rArrdy/dx=3x^-4-2x^-3=3/x^4-2/x^3#
#x=2rArrdy/dx=3/16-2/8=-1/16#
