# How do you find the slope perpendicular to 2x +3y = 6?

I found: $\frac{3}{2}$
First find the slope of your given line changing the form of your equation isolating $y$ in it:
$y = - \frac{2}{3} x + \frac{6}{3}$
$y = - \frac{2}{3} x + 2$ which is in the $y = m x + c$ form called: Slope-Intercept form;
The slope $m$ will be the coefficien of $x$, i.e., $m = - \frac{2}{3}$.
The perpendicular will have slope m$=-1/m or: m$=-1/(-2/3)=3/2