Question

How do you find the slope perpendicular to `x = 0`?

Answer 1

0

Explanation:

Compare to:

The slope for `x=2` is a vertical line perpendicular to the x-axis but crossing the x-axis at `x=2`

So the slope `x=0` is vertical to the axis but crossing it at `x=0`. In other words it is the y-axis.

Slope (gradient) is the amount of up for the amount of along

`-> (y_2 - y_1)/(x_2-x_1)`

The slope for `x=0` can not be quantitised as you are unable to have different values for `x_1 "and x_2`. In fact the only truth is that `x_1=x_2` so you would have `(y_2-y_1)/0` which is undefined!

The perpendicular to the y-axis is parallel to the x-axis. In this case `y_1=y_2 -> 0/(x_2-x_1) = 0` which is defined.

So the slope (gradient) perpendicular to `x=0` is 0.

There is no up for any amount of along!