# How do you find the square root of 16/121?

Mar 31, 2018

$\pm \frac{4}{11}$

#### Explanation:

$16 \text{ and " 121" are both " color(blue)"perfect squares}$

$\text{that is "16=4^2" and } 121 = {11}^{2}$

$\text{also "16=(-4)^2" and } 121 = {\left(- 11\right)}^{2}$

$\Rightarrow \sqrt{\frac{16}{121}} = \pm \frac{4}{11}$

Apr 1, 2018

$\pm \frac{4}{11}$

#### Explanation:

We have the following

$\sqrt{\frac{16}{121}}$ which is equivalent to:

$= \pm \frac{\sqrt{16}}{\sqrt{121}}$

Notice, the numerator and denominator are both perfect squares, that is, we get a integer as an answer. This evaluates to:

$\pm \frac{4}{11}$

NOTE: The $\pm$ sign comes from the fact that when we take the square root of a number, we get a positive and a negative number.

Hope this helps!