# How do you find the standard form of the equation of the parabola with the given characteristic and vertex at the origin and Focus: (0, −5)?

##### 1 Answer

Jan 7, 2017

The equation is

#### Explanation:

The vertex is

The focus is

So the directrix is

Therefore,

Any point on the parabola is equidistant from the focus and the directrix

The equation of the parabola is

graph{(x^2+20y)(y-5)((x)^2+(y+5)^2-0.01)=0 [-12.66, 12.65, -6.33, 6.33]}