How do you find the sum #6+(-4)#? Prealgebra Negative Numbers and Absolute Value Negative Numbers 1 Answer sjc · EZ as pi Dec 29, 2016 #2# Explanation: #6+(-4)# remove the brackets #6+ -4# now #" "+ - =-# #:.=6-4=2# Answer link Related questions How do you compute #-8+13#? How do you compute #11+(-19)#? How do you compute #-19-8#? How do you compute #-77+(-46)#? How do you compute #41+(-56)#? How do you compute #50-82#? How do you compute #-47-13#? How do you compute #-80+102#? How do you compute #5(18)#? How do you compute #-64div(-8)#? See all questions in Negative Numbers Impact of this question 6161 views around the world You can reuse this answer Creative Commons License