How do you find the sum of #Sigma i^2# where i is [0,4]?

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Answer 1 · 2018-03-14T06:20:20

The sum is equal to #30#.

This sigma notation is asking to sum up all square numbers from #0# to #4#.

I'll write out the whole notation:

#color(white)=sum_(i=0)^4i^2#

#=0^2+1^2+2^2+3^2+4^2#

#=0+1+4+9+16#

#=1+4+9+16#

#=5+9+16#

#=14+16#

#=30#

That's the result. I hope this helped!