Question

How do you find the sum of the arithmetic series of `6+12+18+...+96`?

Answer 1

`"sum" = 816`

Explanation:

We can factor our a 6

Hence we are finding `6(1+2+3 + ... + 16 )`

The sum of the first `n` integers is `n/2(n+1)`

We are doing 6 multiplied by the first 16 integers

Hence we get `6 * 16/2 (16+1)`

`= 816`