How do you find the sum of the infinite geometric series 2-2+2-2+..?

1 Answer
Dec 20, 2015

The series diverges by typical summation methods, but may converge depending on the method used.

Explanation:

In general, a geometric series will diverge if the common ratio rr between terms does not have |r| < 1|r|<1. In this case, r = -1r=1, meaning |r| = 1|r|=1 and so the series should diverge.

Still, let's look at this case in a little more detail.

A series sum_(k=0)^ooa_kk=0ak may be defined as lim_(n->oo)sum_(k=0)^na_k.

Typically, we refer to sum_(k=0)^na_k as the n^(th) partial sum of the series (often denoted S_n).

For the series in question, we have

S_n = sum_(k=0)^n(-1)^k*2 = {(2" if n is even"),(0" if n is odd"):}

As the sequence (S_n) simply alternates between 2 and 0, it should be clear that sum_(k=0)^oo(-1)^k*2= lim_(n->oo)S_n does not converge to any value
(the fact that the sequence (S_n) does not converge may be shown simply using an epsilon-delta proof).


The particular series mentioned is similar to a famous series known as Grandi's Series. Like Grandi's series, it diverges in conventional summation, but may converge if another method, such as Cesàro summation, is used.

Numberphile has a nice video on the subject here