Question

How do you find the sum of the infinite geometric series `-2.5(-0.1)^(n - 1)`?

Answer 1

The first term `a_1=-2.5` and common ratio `r=-0.1`

Now use the formula for an infinite geometric sum ...

Explanation:

`S_(oo)=a_1/(1-r)=(-2.5)/(1-(-0.1))=(-25)/11~~-2.2727`

hope that helped