Question

How do you find the sum of the series `1` from i=1 to 42?

Answer 1

You have to use the formula for the sum:

`1+2+3+ ...+n=sum_(i=1)^(i=n) i=(n*(n+1))/2`

Explanation:

So:

`1+2+3+ ...+42=sum_(i=1)^(i=42) i=(42*(42+1))/2=21*43=903`