# How do you find the sum of the series #n^2# from n=1 to 6?

##### 1 Answer

Mar 5, 2017

#### Answer:

#### Explanation:

Adding the individual terms in the sum.

#sum_(n=1)^6n^2#

#=1^2+2^2+3^2+4^2+5^2+6^2#

#=91#

#color(blue)"OR"#

#color(red)"Knowledge of the summation identity"#

#sum_(n=1)^6n^2=1/6n(n+1)(2n+1)# Using n = 6

#=1/6xx6(6+1)(12+1)=1xx7xx13#

#=91#