How do you find the sum of the series #n^2# from n=1 to 6?
1 Answer
Mar 5, 2017
Explanation:
Adding the individual terms in the sum.
#sum_(n=1)^6n^2#
#=1^2+2^2+3^2+4^2+5^2+6^2#
#=91#
#color(blue)"OR"#
#color(red)"Knowledge of the summation identity"#
#sum_(n=1)^6n^2=1/6n(n+1)(2n+1)# Using n = 6
#=1/6xx6(6+1)(12+1)=1xx7xx13#
#=91#
