How do you find the third derivative of #y=sin(2x-5)#?
1 Answer
Apr 27, 2015
y'''= -8cos (2x-5)
The third derivative can be found by differentiating the function three times.
y' = 2 cos(2x-5)
y''= -4 sin (2x-5)
y'''= -8 cos (2x-5)
