# How do you find the two numbers if the greater of two consecutive even integers is 6 less then twice the smaller?

Jun 12, 2015

Substitute $n$ and $n + 2$ into the description to get an equation in $n$ and solve to find the pair $8$ and $10$.

#### Explanation:

Suppose the two integers are $n$ and $n + 2$

Then $\left(n + 2\right) + 6 = 2 n$

Subtract $n$ from both sides to get:

$n = 8$

So the two integers are $n = 8$ and $n + 2 = 10$