# How do you find the two solutions to the sqrt(145)?

Feb 5, 2015

Watch out: the square root of a number $x$ is a unique number, defined as the positive number $y$ such that ${y}^{2} = x$; and in that case, we say that $\setminus \sqrt{x} = y$.

So, the square root of $145$ is a unique number. If you speak of solutions, you are referring to the equation ${x}^{2} - 145 = 0$, which solutions are $\setminus \pm \setminus \sqrt{145}$.