How do you find the value of 325 x 10^-2?

1 Answer
Oct 2, 2015

Answer:

It is #3.25#

Explanation:

If you have to calculate the value of an expression #a*10^n# for an integer value of #n#, the easiest way is to write the value of #a# as a decimal fraction (adding #.0# if #a# is integer) and next move the decimal point #|a|# places tpo the left if #a<0# or to the right if #a>0#

In this case you have:

#a=325#, #n=-2#, so:

1) You write #a# as a decimal fraction #325.0#
2) #n<0#, so you move the decimal point 2 places left, so you get #3.250#
3) Finally you can cross out any zeros at the right end of the number to get #3.25#