Question

How do you find the value of a if `2i` is a root of `z^3-2z^2i+az-32i=0`?

Answer 1

Hence it is a root just replace the value of `z` with `2i` so we get

#(2i)^3-2(2i)^2i+a(2i)-32i=0=> -8i+8i+2ia-32i=0=> 2i(a-16)=0=>a=16#