How do you find the value of k so that (-2, 1) satisfies #kx+ 6y=k#?

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Answer 1 · 2016-10-21T17:31:04

Substitute 2 for x, 1 for y and then solve for k:
#k = 2#

Given:

#kx + 6y = k#

Substitute -2 for x and 1 for y:

#k(-2) + 6(1) = k#

Solve for k:

#3k = 6#

#k = 2#