How do you find the value of #sqrt(6/5)*sqrt(3)# in simplest form?

1 Answer
Alan P.
Mar 24, 2015

Remember that provided the exponent of the radicals are the same (in this case both are square roots so their exponents are both #2#) then the arguments can be multiplied directly under a radical with the same exponent.

Therefore

#sqrt(6/5) * sqrt(3)#

#= sqrt (6/5 * 3)#

#= sqrt( 3^2 * 2 /5)#

#= 3 sqrt(2/5)#

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