How do you find the values of x given #[(x,4,1)][(2,1,0), (1, 0, 2), (0, 2, 4)][(x), (-7), (5/4)]=0#?
1 Answer
Nov 25, 2017
Explanation:
#(0) = ((x, 4, 1))((2,1,0),(1,0,2),(0,2,4))((x),(-7),(5/4))#
#color(white)((0)) = ((2x+4, x+2, 12))((x),(-7),(5/4))#
#color(white)((0)) = (2x^2+4x-7x-14+15)#
#color(white)((0)) = (2x^2-3x+1)#
#color(white)((0)) = ((2x-1)(x-1))#
So:
#x = 1/2" "# or#" "x = 1#
