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How do you find three consecutive even integers such that the sum of the first, third, and twice the second is -16?

1 Answer

Jun 16, 2015

The three consecutive numbers are -6, -4, -2

Explanation:

Let the three consecutive integers be:
$XXXX$ $color(white)("XXXX")$ $(x - 2), (x), and (x + 2)$ $(x-2), (x), and (x+2)$

We are told:
$XXXX$ $color(white)("XXXX")$ $(x - 2) + (x + 2) + 2 (x) = - 16$ $(x-2)+(x+2)+2(x) = -16$

$\Rightarrow$ $rArr$ $XXXX$ $color(white)("XXXX")$ $4 x = - 16$ $4x = -16$

$\Rightarrow$ $rArr$ $XXXX$ $color(white)("XXXX")$ $x = - 4$ $x = -4$

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