# How do you find three consecutive even integers such that the sum of the first, third, and twice the second is -16?

Jun 16, 2015

The three consecutive numbers are -6, -4, -2

#### Explanation:

Let the three consecutive integers be:
$\textcolor{w h i t e}{\text{XXXX}}$$\left(x - 2\right) , \left(x\right) , \mathmr{and} \left(x + 2\right)$

We are told:
$\textcolor{w h i t e}{\text{XXXX}}$$\left(x - 2\right) + \left(x + 2\right) + 2 \left(x\right) = - 16$

$\Rightarrow$$\textcolor{w h i t e}{\text{XXXX}}$$4 x = - 16$

$\Rightarrow$$\textcolor{w h i t e}{\text{XXXX}}$$x = - 4$