How do you find three consecutive even integers such that the sum of twice the first and the third is 2 less than three times the third integer?
1 Answer
Sep 11, 2017
The numbers are 2, 4 and 6
Explanation:
So, we want 3 consecutive even integers. We can represent them by the following notations:
Now for our equation:
- The sum of twice the first and the third:
#2x+2(x+4)# - Two less than three times the third:
#3(x+4)-2#
Now we set those two equal to each other and solve for
So our other two numbers are: