How do you find three consecutive even integers whose sum is 16 more than two times the middle integer?

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Answer 1 · 2016-10-24T04:52:40

The three consecutive even integers are #14#, #16# and #18#.

We shall consider the three consecutive even integers as #x#, #x+2# and #x+4#.

From the details we know that the sum of all three is #16# more than the twice the middle integer.: Expressing this in an equation:

#x+(x+2)+(x+4)=2(x+2)+16#

Opening the brackets and simplifying:

#x+x+2+x+4=2x+4+16#

#3x+6=2x+20#

Shifting terms and simplifying:

#3x-2x=20-6#

#x=14#

#:. x=14, x+2=16, x+4=18#