# How do you find three consecutive integers whose sum is 108?

May 2, 2016

$35 , 36 , 37$

#### Explanation:

Suppose the second integer is $n$. Then the first and third are $n - 1$ and $n + 1$:

$108 = \left(n - 1\right) + n + \left(n + 1\right) = 3 n$

Dividing both ends by $3$ we find:

$n = 36$

So the three integers are:

$35 , 36 , 37$