How do you find three consecutive odd integers that have a sum of 123?

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Answer 1 · 2018-06-04T23:23:51

#39, 41, 43#

Odd integers that are consecutive are #2# apart.

So if the smallest odd integer is called #n#, then the next two odd integers are #n+2# and #n+4#.

We want the sum to be #123#, so

#n + (n+2) + (n+4) = 123#

#3n+6=123#

#3n = 117#

#n = 39#

So the three consecutive odd numbers are: #39, 41, 43#