# How do you find three consecutive odd integers whose sum of the second and third integers is three less then three times the first integer?

Apr 9, 2018

Consider $n$, $n + 1$ and $n + 2$, three consecutive integers. See explanation below

#### Explanation:

$n$, $n + 1$ and $n + 2$. then $n + 1 + n + 2 + 3 = 3 n$

$2 n + 6 = 3 n$

$3 n - 2 n = 6$

$n = 6$ is the first integer and $7$ and $8$ the second and third