Question

How do you find two consecutive even integers such as that the smaller added to three times the larger gives a sum of 38?

Answer 1

I found `8` and `10`.

Explanation:

Call your integers: `2n` and `2n+2`; you need:
`(2n)+3(2n+2)=38`
`2n+6n+6=38`
`8n=32`
`n=4`
So your numbers are:
`2n=8` and `2n+2=10`.