# How do you find two consecutive even integers such as that the smaller added to three times the larger gives a sum of 38?

Jun 29, 2015

#### Answer:

I found $8$ and $10$.

#### Explanation:

Call your integers: $2 n$ and $2 n + 2$; you need:
$\left(2 n\right) + 3 \left(2 n + 2\right) = 38$
$2 n + 6 n + 6 = 38$
$8 n = 32$
$n = 4$
So your numbers are:
$2 n = 8$ and $2 n + 2 = 10$.