# How do you find two consecutive integers such that the sum of the first number and 3 times the second is 55?

Oct 26, 2016

The two consecutive integers are 13 and 14.

#### Explanation:

Let the first integer be $i$.

Then the second integer by definition would be $i + 1$ because these are consecutive integers.

You problem can then be stated as:

$i + 3 \left(i + 1\right) = 55$

Solving for $i$ gives:

$i + 3 I + 3 = 55$

$4 i = 52$

$i = 13$

and therefore
$i + 1 = 14$

$3 \cdot 14 = 42$

$42 + 13 = 55$