How do you find two consecutive odd integers whose sum is 116?

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Answer 1 · 2018-04-28T14:08:11

#57# and #59#

Any odd integer can be written in the form of #2n+1#, where #ninNN#, and even when #n=0#.

So, the two consecutive odd integers would be #2n+1# and #2n+1+2=2n+3#.

Therefore, we get:

#2n+1+2n+3=116#

#4n+4=116#

#4n=112#

#n=112/4#

#=28#

#:.2n+1=2*28+1#

#=57#

#2n+3=2*28+3#

#=59#

Therefore, the two consecutive integers are #57# and #59#.