# How do you find two integers whose sum is 6 and with a difference of 4?

Nov 10, 2015

I found $5$ and $1$

#### Explanation:

yo can call your integers $x$ and $y$ and form the two equations:
$x + y = 6$
$x - y = 4$
from the first you have:
$x = 6 - y$ that substituted into the second gives:
$6 - y - y = 4$ rearranging:
$2 y = 2$
$y = \frac{2}{2} = 1$
Back into $x = 6 - y$
$x = 6 - 1 = 5$