Question

How do you find two integers whose sum is 6 and with a difference of 4?

Answer 1

I found `5` and `1`

Explanation:

yo can call your integers `x` and `y` and form the two equations:
`x+y=6`
`x-y=4`
from the first you have:
`x=6-y` that substituted into the second gives:
`6-y-y=4` rearranging:
`2y=2`
`y=2/2=1`
Back into `x=6-y`
`x=6-1=5`