# How do you find vertices, foci, directrix, axis of symmetry of #Y+2 =1/10(x-6)^2#?

##### 1 Answer

Nov 29, 2016

The vertex is

The focus is

The directrix is

The axis of symmetry is

#### Explanation:

We rewrite the equation as

We compare this to the equation

The vertex is

The focus is

The directrix is

The axis of symmetry is

graph{(x-6)^2=10(y+2) [-36.54, 36.54, -18.27, 18.28]}