How do you find #w(3n)# given #w(n)=4n+2#?
1 Answer
May 7, 2018
Explanation:
#"to evaluate "w(3n)" substitute "n=3n" into "w(n)#
#rArrw(color(red)(3n))=4(color(red)(3n))+2=12n+2#
#"to evaluate "w(3n)" substitute "n=3n" into "w(n)#
#rArrw(color(red)(3n))=4(color(red)(3n))+2=12n+2#